Concentric metallic hollow spheres of radii $R$ and $4 R$ hold charges $Q _{1}$ and $Q _{2}$ respectively. Given that surface charge densities of the concentric spheres are equal, the potential difference $V ( R )- V (4 R )$ is
JEE MAIN 2020, Medium
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$E =\frac{ KQ _{1}}{ r ^{2}}$
$\Delta V =\int_{ R }^{4 R } E dr =\frac{3 KQ _{1}}{4 R }$
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