d
When connected in parallel $C _{ eq }= C _{1}+ C _{2}$
When in series
$C _{ eq }^{\prime}=\frac{ C _{1} C _{2}}{ C _{1}+ C _{2}}$
$C _{1}+ C _{2}=\frac{15}{4}\left(\frac{ C _{1} C _{2}}{ C _{1}+ C _{2}}\right)$
$4\left( C _{1}+ C _{2}\right)^{2}=15 C _{1} C _{2}$
$4 C _{1}{ }^{2}+4 C _{2}^{2}-7 C _{1} C _{2}=0$
dividing by $C _{1}{ }^{2}$
$4\left(\frac{ C _{2}}{ C _{1}}\right)^{2}-\frac{7 C _{2}}{ C _{1}}+4=0$
Let $\frac{ C _{2}}{ C _{1}}= x$
$4 x^{2}-7 x+4=0$
$b ^{2}-4 ac =49-64<0$
No solution exits981-s782