Consider the following ionization enthalpies of two elements 'A' … - Vidyadip

MCQ

Consider the following ionization enthalpies of two elements $'A'$ and $'B'$.

Element	Ionization	enthalpy	$(kJ/mol)$
	$1^{st}$	$2^{nd}$	$3^{rd}$
$A$	$899$	$1757$	$14847$
$B$	$737$	$1450$	$7731$

Which of the following statements is correct ?

A
Both $'A'$ and $'B'$ belong to group $-1$ where $'B'$ comes below $'A'$.
B
Both $'A'$ and $'B'$ belong to group $-1$ where $'A'$ comes below $'B'$.
✓
Both $'A'$ and $'B'$ belong to group $-2$ where $'B'$ comes below $'A'$.
D
Both $'A'$ and $'B'$ belong to group $-2$ where $'A'$ comes below $'B'$

✓

Answer

Correct option: C.

Both $'A'$ and $'B'$ belong to group $-2$ where $'B'$ comes below $'A'$.

c
Generally, the ionization enthalpies or energy increases from left to right in a period and decreases from top to bottom in a group. Several factor such as atomic radius, nuclear charge, shielding effect are responsible for change of ionization enthalpies Here, $1^{st}$ ionization enthalpy of $A$ and $B$ is greater than group $I$ ($Li\, 520\, kJ\,mol^{-1}$ to $Cs\,374\, kJ\,mol^{-1}$), which means element $A$ and $B$ belong to group $-2$ and all three given ionization enthalpy values are less for element $B$ means $B$ will come below $A$.

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