MCQ
Consider the following reaction

$N _{2} O _{4}( g ) \rightleftharpoons 2 NO _{2}( g ) ; \Delta H ^{0}=+58 kJ$

For each of the following cases $(a, b),$ the direction in which the equilibrium shifts is:

$(a)$ Temperature is decreased

$(b)$ Pressure is increased by adding $N _{2}$ at constant $T$

  • $(a)$ towards reactant, $(b)$ no change
  • B
    $(a)$ towards product, $(b)$ towards reactant
  • C
    $(a)$ towards product, $(b)$ no change
  • D
    $(a)$ towards reactant, $(b)$ towards product

Answer

Correct option: A.
$(a)$ towards reactant, $(b)$ no change
a
$\Delta H ^{\circ}>0 \quad T \downarrow$ equation shifts back ward.

$N _{2}$ is treated as inert gas in this case hence no effect on equilibrium.

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