MCQ
Consider the junction diode as ideal. The value of current flowing through AB is
- A(0 A)
- ✓10-2A
- C10-1A
- D10-3A
✓
Answer
Correct option: B.
10-2A
(B)10-2A
In forward bias, resistance of diode will be zero.
$i =\frac{ V _{ A }- V _{ B }}{ R }$
$=\frac{4-(-6)}{1 \times 10^3}$
$i =\frac{10}{10^3}=10^{-2} amp$
In forward bias, resistance of diode will be zero.
$i =\frac{ V _{ A }- V _{ B }}{ R }$
$=\frac{4-(-6)}{1 \times 10^3}$
$i =\frac{10}{10^3}=10^{-2} amp$
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