Consider the reaction between $\ce{C_2H_{5}O^{⊝ }}$ and dimethyl sulphate. The leaving group in this reaction is$:$
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The compound $A$ on treatment with $Na$ gives $B,$ and with $\ce{PCI_{5 }}$ gives $C. B$ and $C$ react together to give diethyl ether. $A, B$ and $C$ are in the order.