Among given compounds, ethylene glycol $\ce{(HO−CH_{2}−CH_2−OH)}$ is the most soluble in water. Ethylene glycol has two hydroxy groups both of which form hydrogen bonds with water. Greater is the number of hydrogen bonds, greater is the extent of hydrogen bonding and greater is the solubility in water.
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When $3-$methylbutan$-2-$ol is treated with $\ce{HBr},$ the following reaction takes place. What are the correct steps for formation of the above product?