Question
Construct a quadrilateral $ABCD$ given that $AB = 4\ cm, BC = 3\ cm,$
$\angle\text{A}=75^\circ,$
$\angle\text{B}=80^\circ$ and $\angle\text{C}=120^\circ.$
$\angle\text{A}=75^\circ,$
$\angle\text{B}=80^\circ$ and $\angle\text{C}=120^\circ.$
✓
Answer
Steps of construction:
Step I: Draw $AB = 4\ cm.$
Step II: Construct $\angle\text{XAB}=75^\circ$ at $A$ and $\angle\text{ABY}=80^\circ$ at $B.$
Step III: With $B$ as the centre and radius $3\ cm,$ cut off $BC = 3\ cm.$
Step IV: At $C,$ draw $\angle\text{BCZ}=120^\circ$ such that it meets $AX$ at $D.$
The quadrilateral so obtained is the required quadrilateral.
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