Question
Construct a rhombus whose perimeter is $16\ cm$ and $BD = 6.2\ cm.$
✓
Answer
The length of all the sides of rhombus is equal.
Hence, perimeter $=$ side $\times 4$
$ \Rightarrow$ Side
$=\frac{\text { perimeter }}{4}$
$=\frac{16}{4}$
$=4 \ cm $
Steps of construction:
$1$) Draw $BD =6.2 \ cm$.
$2)$ With $B$ as centre and radius $4 \ cm$, draw two arcs one above $B D$ and the other below $B D$.
$3)$ With $D$ as centre and radius $4 \ cm$ draw two arcs one above $B D$ and the other below $B D$ intersecting the arcs of Steps $2$ in $A$ and $C$ respectively.
$4)$ Join $A B, B C, C D$ and $A D$.
$5)\text{ABCD}$ is the required rhombus.
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