Question
$\cos \alpha .\sin (\beta - \gamma ) + \cos \beta .\sin (\gamma - \alpha ) + \cos \gamma .\sin (\alpha - \beta ) = $
$\alpha = \beta = \gamma = {60^o} $ रखने पर
$\Rightarrow \frac{1}{2}(0) + \frac{1}{2}(0) + \frac{1}{2}(0) = 0$.
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