Question
$\cos x\frac{{dy}}{{dx}} + y\sin x = 1$ का हल है
$\frac{{dy}}{{dx}} + y\tan x = \sec x$
$\therefore $ $I.F.$ $ = {e^{\int_{}^{} {\tan xdx} }} = {e^{\log \sec x}} = \sec x$
अत: इसका हल है $y\sec x = \int_{}^{} {{{\sec }^2}x + c} = \tan x + c$
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