MCQ
$\cos x\frac{{dy}}{{dx}} + y\sin x = 1$ નો ઉકેલ મેળવો.
- A$y\sec x\tan x = c$
- ✓$y\sec x= \tan x c$
- C$y\tan x = \sec x + c$
- D$y\tan x = \sec x\tan x + c$
$\therefore $ $I.F.$ $ = {e^{\int_{}^{} {\tan xdx} }} = {e^{\log \sec x}} = \sec x$
Hence solution is $y\sec x = \int_{}^{} {{{\sec }^2}x + c} = \tan x + c$.
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