MCQ
$cos^273^o + cos^247^o + (cos73^o . cos47^o )$ =
- A$1/4$
- B$1/2$
- ✓$3/4$
- D$1$
$= 1 +$ $\left[ {\frac{{\cos {{146}^o }\, + \cos {{94}^o }}}{2}} \right]\,\, - \,\,\frac{1}{4}\, + \,\frac{{\cos {{26}^o }}}{2}$
$= 3/4$
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