$Cu^{2+} (aq) + Fe\,(s) \rightleftharpoons Fe^{2+} \,(aq) + Cu\,(s)$ પ્રક્રિયા માટે $\Delta G^o$ ............... જૂલમાં ગણો.

${{\text{E}}^o }{\text{C}}{{\text{u}}^{{\text{2}} + }}{\text{/Cu = + 0}}{\text{.34 V, E}}_{{\text{F}}{{\text{e}}^{ + {\text{2}}}}/Fe}^o = \,\,{\text{ - 0}}{\text{.44 V}}$

Question

$Cu^{2+} (aq) + Fe\,(s) \rightleftharpoons Fe^{2+} \,(aq) + Cu\,(s)$ પ્રક્રિયા માટે $\Delta G^o$ ............... જૂલમાં ગણો.

${{\text{E}}^o }{\text{C}}{{\text{u}}^{{\text{2}} + }}{\text{/Cu = + 0}}{\text{.34 V, E}}_{{\text{F}}{{\text{e}}^{ + {\text{2}}}}/Fe}^o = \,\,{\text{ - 0}}{\text{.44 V}}$

A$-132648$
B$-153698$
C$-125698$
D$-150540$

Diffcult

Download our app for free and get started

Solution

d
કોષ પ્રક્રિયા

$Fe\,(s)\,\, \to \,\,F{e^{2 + }}(aq)\,\, + \,\,2{e^ - }$ ....... એનોડ પર

$C{u^{2 + }}(aq)\, + \,\,2{e^ - }\, \to \,\,Cu\,\,(s)$ ........ કેથોડ પર

આપણે જાણીએ છીએ :

$\Delta \,{G^o } = \,- \,n\,F\,E_{cell}^o$ ; $n= 2$

$E_{cell}^o = \,\left[ {E_{(C{u^{2 + }}/cu)}^o - E_{(F{e^{2 + }}/Fe)}^o} \right]$

$ = ( + \,0.34\,V\,)\,- \,( - 0.44\,V)= +0.78\,V$ અને

$F= 96500\,C$

$\therefore \,\Delta \,{G^o } = \,- \,n\,\,F\,E_{cell}^o \,= \, - (2)\,\, \times \,(96500\,C)\,\, \times \,( + \,0\,.78\,V)$

$ = \,- 150540\,\,CV\, = \, - \,150540\,J$

$\,(\;\because \,1\,CV\, = \,1\,J)$

$ClO_4^{-}$	$IO_4^{-}$	$BrO_4^{-}$
$E^{\circ}=1.19 V$	$E^{\circ}=1.65 V$	$E^{\circ}=1.74 V$

Download our app
and get started for free

Similar Questions

Download our appand get started for free

Similar Questions

Download our app
and get started for free