$\mathrm{Cu}^{2 \mathrm{+}}+2 \mathrm{e}^{-} \longrightarrow \mathrm{Cu} \quad 0.34 \quad=-2 \mathrm{F}(0.34)$
$\mathrm{Cu}^{+}+\mathrm{e}^{-} \longrightarrow \mathrm{Cu} \quad \quad 0.522 \quad=-\mathrm{F}(0.522)$
$\mathrm{Cu}^{2 \mathrm{+}}+\mathrm{e}^{-} \longrightarrow \mathrm{Cu}^{+}$
$\Delta \mathrm{G}^{0}=-2 \mathrm{F}(0.34)-(-\mathrm{F}(0.522))$$=-\mathrm{F}(0.68-0.522)=-F(0.158)$
$\mathrm{E}^{0}=\frac{-\mathrm{F}(0.158)}{-\mathrm{F}}=0.158 \mathrm{V}$
$MnO _{4}^{-}+8 H ^{+}+5 e ^{-} \rightarrow Mn ^{2+}+4 H _{2} O$,
$E^{o} _{ Mn ^{2+} / MnO _{4}^{-}}=-1.510 \,V$
$\frac{1}{2} O _{2}+2 H ^{+}+2 e ^{-} \rightarrow H _{2} O$,
$E _{ O _{2} / H _{2} O }^{o}=+1.223 \,V$
એસિડની હાજરીમાં પાણીમાંથી પરમેંગેનેટ આયન $MnO _{4}^{-}$એ $O _{2}$ મુક્ત કરશે?