$Fe \rightarrow Fe^{2+} + 2e^{-} , E^{o} = 0.44\,\, V , 2H^{+} + 2e^{-} + \frac{1}{2} O_2 \rightarrow H_2O_{(l)}, E_{o} = 1.23\, V$ તો આ પ્રક્રિયા માટે $\Delta G^{o} =....$ કિલોજૂલ / મોલ
\(2{H^ + } + 2{e^ - } + \frac{1}{2}{O_2} \to {H_2}{O_{(l)}}\,\) માટે
\(\Delta {{\text{G}}_{\text{2}}}^{\text{0}}{\text{ = - nF}}{{\text{E}}^{\text{0}}}{{\text{ }}_{{\text{cell2}}}}{\text{ = ( - 2 }} \times {\text{ 96500 }} \times {\text{ 1}}{\text{.23)}}\)
\(Fe + 2{H^ + } + \frac{1}{2}{O_2} \to F{e^{2 + }} + {H_2}O\) માટે \(\Delta {{\text{G}}_{\text{3}}}^{\text{0}}{\text{ = }}\Delta {{\text{G}}_{\text{1}}}^{\text{0}}{\text{ + }}\Delta {{\text{G}}_{\text{2}}}^{\text{0}}\)
\(\Delta G_3^{0} = (-2 × 96500 × 0.44) + (-2 × 96500 ×1.23) = -322310\) જૂલ \(= -322.310 \) કિલોજૂલ \(= -322\) કિલોજૂલ/મોલ
$= + 0.34 \,volt, I_2/ 2I- = + 0.53\, volt$