MCQ
${d \over {dx}}{\log _{\sqrt x }}(1/x) = . . . .$
- A$ - {1 \over {2\sqrt x }}$
- B$-2$
- C$ - {1 \over {{x^2}\sqrt x }}$
- ✓$0$
$= \frac{{\log \left( {\frac{1}{x}} \right)}}{{\log \sqrt x }} $
$= \frac{{( - 1)\log x}}{{(1/2)\,\log x}} = - 2$
==> $f'(x) = 0$.
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$f(x) \rightarrow \frac{\lambda\left|x^{2}-5 x+6\right|}{\mu\left(5 x-x^{2}-6\right)}, x<2$
$\quad\quad\quad\quad e^{\frac{\tan (x-2)}{x-[x]}}, \quad x>2$
$\quad\quad\quad\quad \mu \quad\quad\quad\quad x=2$
કે જ્યાં $[x]$ એ મહતમ પૃણાંક વિધેય છે. જો $f$ એ $x=2$ આગળ સતત હોય તો $\lambda+\mu$ ની કિમંત મેળવો.