MCQ
$\frac{d}{d x} \tan ^{-1}\left(\frac{x}{1+6 x^2}\right)=$........ .
- ✓$\frac{3}{1+9 x^2}-\frac{2}{1+4 x^2}$
- B$\frac{3}{1+9 x^2}+\frac{2}{1+4 x^2}$
- C$\frac{1}{1+9 x^2}-\frac{1}{1+4 x^2}$
- D$\frac{\left(1+6 x^2\right)^2}{1+7 x^2}$
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