MCQ
$(\Delta H - \Delta U)$ for the formation of carbon monoxide $(CO)$ from its elements at $298\, K$ is ............. $\mathrm{J\,mol}^{-1}$ $(R= 8.314\,J\,K^{-1}\, mol^{-1})$
- A$- 2477.57$
- B$2477.57$
- C$-1238.78$
- ✓$1238.78$
$\Delta H=\Delta U+\Delta n R T$
or $\quad \Delta H-\Delta U=\Delta n R T$
$\Delta n=1-\frac{1}{2}=\frac{1}{2}$
$\Delta H-\Delta U=\frac{1}{2} \times 8.314 \times 298$
$=1238.78 \,J \,m o l^{-1}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

$C$ $ (graphite) $ $ + {O_2}(g) \to C{O_2}(g);\,\Delta H = - 393.5$
If the graphite is made of diamond then the above figure is $\Delta H$.......$kJ$