Question
Derive the equation
$V^2-u^2 = 2as$
$V^2-u^2 = 2as$
✓
Answer
In figure we know
$S=$ area of trapezium OSQP
Area of trapezium OSQP $=\frac{1}{2}$ \{sum of parallel sides) $x$ perpendicular distance between them.
$ S=\frac{1}{2}(O P+S Q) \times P R .$
$P R=Q R / a=(Q S-R S) / a$
$P R=(v-u) / a=t $
So $P R=t$.
Substituting these values in expression of area of trapezium we get $S=Y$. $\{u+v) \times t S={ }^{\prime} 1 / 2(u+v) \times(u$
$ -v) / a .$
$2 a S=v^2-u^2$
$v^2-u^2=2 a s . $
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