
$\mathrm{d}_{2}=\frac{6}{8}=\frac{3}{4} \mathrm{m} / \mathrm{sec}^{2}$

(Assume forces on the four tyres are identical and $g =$ acceleration due to gravity)

(considering $4\ kg$ block doesn't fall on ground)
Consider the following statements
$(i)$ Time when relative motion between them is stopped is $1.4\ second$.
$(ii)$ Time when relative motion between them is stopped in $1.2\ second$
$(iii)$ The common velocity of the two blocks is $8\ m/s$, towards right.
$(iv)$ The displacement of the $4\, kg$ block when relative motion stopped is$10.8\ m$.
Which of the fstatements is/are correct

