વિધાન $ 1: $ જો $A \ne I,A \ne - I$ તો $\det \left( A \right) = - 1$
વિધાન $2:$ જો $A \ne I,A \ne - I$ તો ${\rm{tr}}\left( A \right) \ne 0$
${A^2} = \left[ {\begin{array}{*{20}{c}}
a&b\\
c&d
\end{array}} \right]\left[ {\begin{array}{*{20}{c}}
a&b\\
c&d
\end{array}} \right]$
$ = \left[ {\begin{array}{*{20}{c}}
{{a^2} + bc}&{ab + bd}\\
{ac + cd}&{bc + {d^2}}
\end{array}} \right] = I$
${a^2} + bc = bc + {d^2} = 1$
$ac + cd = ab + bd = 0$
$ac + cd = ab + bd = 0$
$b\left( {a + d} \right) = 0$
$c = 0\;\:{\rm{or}}\;\:a = - d$ not possible for $c$
$b = 0\;\:{\rm{or}}\;\:a = - d$ not possible for $b$
$\left| {\begin{array}{*{20}{c}}
a&b\\
c&d
\end{array}} \right| = ad - bc = - {d^2} - bc$
$ = - \left( {{d^2} + bc} \right) = - 1$
$tr\left( A \right) = a + d = a - a = 0$
$x+y+z=6$
$x+2 y+\alpha z=10$
$x+3 y+5 z=\beta$, નીચે ના પૈકી ક્યૂ અસત્ય છે ?