MCQ
Difference in density is the basis of
- AUltrafiltration
- BMolecular sieving
- ✓Gravity Separation
- DMolecular attraction
✓
Answer
Correct option: C.
Gravity Separation
c
In case of ultrafiltration it is particle size of micron sizes present in liquid or gas are getting filtered.
In case of ultrafiltration it is particle size of micron sizes present in liquid or gas are getting filtered.
In molecular sieving, permeability of molecular sieve membranes based on the size and shape of the molecules is employed.
In gravity separation difference in density of particles is employed
In molecular attraction, mainly exchange of cations to anions among given two molecules.
In atomic absorption ,elements are identified based on the absorption of optical radiation by free atoms in gaseous state.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Plumbous ion is represented as :
Which of the following is a meso compound ?
Product $(A)$ of the reaction is
→For the reaction equilibrium ${N_2}{O_4}$ $\rightleftharpoons$ $2N{O_{2(g)}}$, the concentrations of ${N_2}{O_4}$ and $N{O_2}$ at equilibrium are $4.8 \times {10^{ - 2}}$and $1.2 \times {10^{ - 2}}\,mol\,litr{e^{ - 1}}$ respectively. The value of ${K_c}$ for the reaction is
→Presence of a nitro group in a benzene ring:
Which of the following has trigonal planar geometry?
Molecular mass, melting point and boiling point of water respectively are:
Alkali metals react with water vigorously to form hydroxides and dihydrogen. Which of the following alkali metals reacts with water least vigorously?
The molecular orbitals like atomic orbitals are filled in accordance with the :
Arrange the following alkanes in decreasing order of their heats of combustion
→$(i)\,\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,C{H_3}} \\
| \\
{C{H_3} - C - C{H_3}} \\
| \\
{\,\,\,\,\,C{H_3}}
\end{array}}\limits_{(Neo - pen\tan e)\,(i)} $
$(ii\mathop {)\,\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2} - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,\,\,\,C{H_{3\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}}}
\end{array}}\limits_{(Iso - pen\tan e)\,\,(ii)} $
$(iii)\,\mathop {C{H_3} - C{H_2} - C{H_2} - C{H_2} - C{H_3}}\limits_{(n - pen\tan e)} $