Question
Discuss the Einstien's explanation for the photoelectric effect.
✓
Answer
$\rightarrow$ In $1905,$ Einstien gave a historical explanation of the photoelectric effect.
For which he was awarded the Nobel prize in physics in $1921$.
$\rightarrow$ Einstein accepted Max Planck's concept of radiation.
$\rightarrow$ According to this concept, the energy of radiation is not continuous.
Radiation is composed of discrete units of energy, $($Bundles of energy$)$
These units of energy are called quanta or photons.
Each quantum (photon) has energy $E =h v$.
Where, $h=$ Planck's constant
$h=6.625 \times 10^{-34} J s$
$v=$ Frequency of radiation
$\rightarrow$ When radiation is incident on a metal surface, the electrons in the metal interact with the quanta of the radiation.
If the energy of quantum $(h v)$ is greater than the work function $\left(\phi_0\right)$ of a given metal, the electron absorbs this quantum. i.e. the full energy of the quantum $(h v)$ is absorbed and is emitted from the metal with a maximum kinetic energy $K _{\max }$.
Thus, $K _{ max }=h v-\phi_0$
$\rightarrow$ This equation is called Einstein's equation of photoelectric effect.
$\rightarrow$ If a photon interacts with an strongly bound electron than electron requires more energy to be ejected.
So it is emitted with less energy than $K _{\max }$.
For which he was awarded the Nobel prize in physics in $1921$.
$\rightarrow$ Einstein accepted Max Planck's concept of radiation.
$\rightarrow$ According to this concept, the energy of radiation is not continuous.
Radiation is composed of discrete units of energy, $($Bundles of energy$)$
These units of energy are called quanta or photons.
Each quantum (photon) has energy $E =h v$.
Where, $h=$ Planck's constant
$h=6.625 \times 10^{-34} J s$
$v=$ Frequency of radiation
$\rightarrow$ When radiation is incident on a metal surface, the electrons in the metal interact with the quanta of the radiation.
If the energy of quantum $(h v)$ is greater than the work function $\left(\phi_0\right)$ of a given metal, the electron absorbs this quantum. i.e. the full energy of the quantum $(h v)$ is absorbed and is emitted from the metal with a maximum kinetic energy $K _{\max }$.
Thus, $K _{ max }=h v-\phi_0$
$\rightarrow$ This equation is called Einstein's equation of photoelectric effect.
$\rightarrow$ If a photon interacts with an strongly bound electron than electron requires more energy to be ejected.
So it is emitted with less energy than $K _{\max }$.
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