Question
$\frac{d}{{dx}}\{ {e^{ - a{x^2}}}\log (\sin x)\} = $
$ = {e^{ - a{x^2}}}( - 2ax).\log (\sin x) + {e^{ - a{x^2}}}\cot x$
$ = {e^{ - ax}}^2[\cot x - 2ax\log (\sin x)]$.
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