\(V _{ C }=\frac{ K (\Sigma q )}{ R }\)
\(V _{ C }=\frac{ K (0)}{ R }=0\)
Electric field at centre \(\overrightarrow{ E }_{ B }=\Sigma \overrightarrow{ E }\)
Let \(E\) be electric field produced by each charge at the centre, then resultant electric field will be
\(E _{ C }=0,\) since equal electric field vectors are acting at equal angle so their resultant is equal to zero.
વિધાન $-2$ : $6.4\times10^6\, m$ ત્રિજ્યા ધરાવતી પૃથ્વી માટે આ શક્ય છે.