MCQ
The number of atoms in $0.1\, mol$ of a triatomic gas is $(N_A = 6.02\times10^{23}\, mol^{-1})$
  • A
    $1.800\times10^{22}$
  • B
    $6.026\times10^{22}$
  • $1.806\times10^{23}$
  • D
    $3.600\times10^{23}$

Answer

Correct option: C.
$1.806\times10^{23}$
c
$ \text { No. of atoms } =0.1 \times \mathrm{N}_{\mathrm{A}} \times 3 $

$=0.1 \times 6.02 \times 10^{23} \times 3 $

$=1.806 \times 10^{23}$

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