MCQ
The number of atoms in $0.1\, mol$ of a triatomic gas is $(N_A = 6.02\times10^{23}\, mol^{-1})$
- A$1.800\times10^{22}$
- B$6.026\times10^{22}$
- ✓$1.806\times10^{23}$
- D$3.600\times10^{23}$
$=0.1 \times 6.02 \times 10^{23} \times 3 $
$=1.806 \times 10^{23}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.