MCQ
$\frac{{dy}}{{dx}} = 1 + x + {y^2} + x{y^2},y\left( 0 \right) = 0,$ નો ઉકેલ $............$
- A${y^2} = 1 + c\,\exp .\left( {x + \frac{{{x^2}}}{2}} \right)$
- B$y = \tan \left( {c + x + {x^2}} \right)$
- ✓$y = \tan \left( {x + \frac{{{x^2}}}{2}} \right)$
- D${y^2} = \exp .\left( {x + \frac{{{x^2}}}{2}} \right) - 1$