Each of the two strings of length $51.6\,\, cm$ and $49.1\,\, cm$ are tensioned separately by $20\,\, N$ force. Mass per unit length of both the strings is same and equal to $1\,\, g/m.$ When both the strings vibrate simultaneously the number of beats is
A$7$
B$8$
C$3$
D$5$
AIPMT 2009, Medium
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A$7$
a $l_{1}=0.516 \mathrm{m}, l_{2}=0.491 \mathrm{m}, T=20 \mathrm{N}$
Mass per unit length, $\mu=0.001 \mathrm{kg} / \mathrm{m}$
$\therefore \quad$ Number of beats $=v_{1}-v_{2}=7$
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