(i.e $en$ and $C_2O_4$ ), so coordination number of $E$ is $6$
$(2 \times 2 + 1 \times 2 = 6)$
Let the oxidation state of $E$ in complex be $x$, then
$[x + (-2) = 1]$ or $x -2 = 1$
or $x = + 3$, so its oxidation state is $+ 3$ Thus option $(d)$ is correct.
[પ.ક્ર.: $Cr= 24,\,Mn= 25, \,Fe= 26, \,Co= 27$]