$[E(en)_2(C_2O_4)]NO_2$ સંકીર્ણ માં તત્વ $‘E’$ નું સવર્ગાક અને ઓક્સિડેશન આંક (જ્યાં $en$ એ ઇથિલીન ડાયએમાઈન) અનુક્રમે શું હશે ?

Question

AIIMS 2014, Diffcult

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Solution

d
In the given complex we have two bidentate ligands

(i.e $en$ and $C_2O_4$ ), so coordination number of $E$ is $6$

$(2 \times 2 + 1 \times 2 = 6)$

Let the oxidation state of $E$ in complex be $x$, then

$[x + (-2) = 1]$ or $x -2 = 1$

or $x = + 3$, so its oxidation state is $+ 3$ Thus option $(d)$ is correct.

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