$(1mol)$ $(1 \mathrm{mol})$
$\mathrm{MOH}+\frac{1}{2} \mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \frac{1}{2} \mathrm{M}_{2} \mathrm{SO}_{4}+\mathrm{H}_{2} \mathrm{O}$
$(1mol) $$\left(\frac{1}{2} \mathrm{mol}\right)$
So one mole of HCl required to react with one mole $MOH.$
So $\frac{1}{2}$ mole of $\mathrm{H}_{2} \mathrm{SO}_{4}$ required to react with one mole $MOH.$
$2{C_{57}}{H_{110}}{O_6}(s)\, + \,163\,{O_2}(g)\, \to \,114\,C{O_2}(g)\, + \,110\,{H_2}O(l)$