$\left(\mathrm{R}=0.083 \mathrm{~L}\right.$ bar mol-1 $\mathrm{K}^{-1}$ નો ઉપયોગ કરો)
$ \text { Slope }=R T $
$ 25.73=0.083 \times T $
$T=\frac{25.73}{0.083}=309.47 \approx 310 \mathrm{~K}$
$\therefore \quad \text { Temperature in }{ }^{\circ} \mathrm{C} $$ =310-273 $
$ =37^{\circ} \mathrm{C}$