\(T_f = 273 + 16.6 = 289.6\,K\)
\(L_f = 180.75\,J/g\)
\(K_f = 3.86\)
$\left[\right.$ આપેલ છે $\left.: {K}_{{f}}\left({H}_{2} {O}\right)=1.86\, {~K}\, {~kg}\, {~mol}^{-1}\right]$
(પાણી માટે $K_f = 1.86\,^oC\, kg\, mol^{-1}$ છે)
(મોલર દળ $S = 32\, g\, mol^{-1}, Na = 23\, g\, mol^{-1}$ )