\(\therefore \,\,E\,\, = \,\,\frac{{{h^2}}}{{2m{\lambda ^2}}}\,\,\,\lambda \) અચળ હોવાથી \({\text{E}}\,\, \propto \,\,\frac{{\text{1}}}{{\text{m}}}\)
અહીં \({\text{, }}{{\text{m}}_{\text{e}}}{\text{ < }}{{\text{m}}_{\text{p}}}\)
હોવાથી \({{\text{E}}_{\text{e}}}{\text{ > }}{{\text{E}}_{\text{p}}}\)