d
\(\Delta {I_B}\, = \,\,150\,\mu A\,\, - \,\,100\,\,\mu A\,\, = \,\,50\,\,\mu A\,\, = \,\,50\,\, \times \,\,{10^{ - 6}}A\)

\(\Delta {I_C} = \,\,10\,mA\,\, - \,\,5\,mA\,\,\, = \,\,5mA\,\, = \,\,5\,\, \times \,\,{10^{ - 3}}\,A\)

હવે, \(\beta \,\, = \,\, \frac{{\Delta {I_C}}}{{\Delta {I_B}}}\,\, = \,\,\frac{{5\,\, \times \,\,{{10}^{ - 3}}}}{{50\,\, \times \,{{10}^{ - 6}}}}\,\, = \,\,100\)