Initial volume \(V=(\text { side })^3=\left(10 \times 10^{-2}\right)^3\)

\(P=7 \times 10^6 \,Pa\)

\(B=140 \times 10^9 \,Pa\)

We know

\(\frac{-\Delta V}{V}=\frac{P}{B} \quad\{-\Delta V=\text { Contraction in volume }\}\)

\(\frac{-\Delta V}{10^{-3}}=\frac{7 \times 10^6}{140 \times 10^9}\)

\(-\Delta V=5 \times 10^{-8} \,m ^3\)