\(\therefore \mathrm{E}=\mathrm{vB}\)
And Gauss's law in Electrostatics \(\mathrm{E}=\frac{\sigma}{\varepsilon_{0}}\)
\(\mathrm{E}=\frac{\sigma}{\varepsilon_{0}}=\mathrm{vB} \Rightarrow \sigma=\varepsilon_{0} \mathrm{vB}\)
\(\sigma_{1}=-\sigma_{2}\)