Given, \(t_2-t_1=10 s\)
\(t_2+t_1=\frac{2 u}{g}=\frac{2 \times 52}{10}=10.4\)
\(\Rightarrow 2 t_2=20.4\)
\(\Rightarrow t_2=10.2 \,s\)
\(t_1=0.2 \,s\)
So, \(t_1 t_2=\frac{2 h}{g}\)
\(0.2 \times 10.2=\frac{2 \times h}{10}\)
\(\Rightarrow 1 \times 10.2=h \Rightarrow 10.2 \,m =h\)