\(SD =2-\frac{1}{3}=\frac{5}{3}\)

Area of \(OABS\) is \(A _{1}\)

Area of \(SCD\) is \(A _{2}\)

Distance \(=\left| A _{1}\right|+\left| A _{2}\right|\)

\(A _{1}=\frac{1}{2}\left[\frac{13}{3}+1\right] 4=\frac{32}{3}\)

\(A _{2}=\frac{1}{2} \times \frac{5}{3} \times 2=\frac{5}{3}\)

Distance \(=\left|A_{1}\right|+\left|A_{2}\right|\)

\(=\frac{32}{3}+\frac{5}{3}\)

\(=\frac{37}{3}\)