\(r = 50\,cm = \frac{{50}}{{100}}m = 0.5\,m,\,\,\,\)

\( = \,\,20\,\) ભ્રમણ \( = \,\,20\,\, \times \,\,2\pi \,rad\,  = \,\,40\, \pi \,\,rad\,\,\, = \,\,{\upsilon _1} = r{\omega _1}\)

\(\,\therefore \,\,\,{\omega _1} = \frac{{{\upsilon _1}}}{r} = \frac{{15}}{{0.5}} = 30\,rad\,{s^{ - 1}},\,\,\,{\omega _2} = 0,\,d = ?,\,\alpha  = ?\)

હવે, \(\alpha  = \frac{{\omega _2^2 - \omega _1^2}}{{2\theta }} = \frac{{0 - 900}}{{2 \times 40\pi }} =  - 3.58\,rad\,{s^{ - 2}}\,\,\)

\( \Rightarrow \,\,\) ઍક પરિભ્રમન \({\text{ =  2}}\pi {\text{r}}\)

રેખીય અંતર \(\therefore \,\,\,20\,\) પરિભ્રમન \( = \,\,20\,  \times \, 2\pi r\) રેખીય અંતર 

ટ્રકે કાપેલું અંતર \( \Rightarrow \,\,d\,\, = \,\,20\,  \times \,\,2\,\, \times \,\,3.14\,\, \times \,\,0.5\,\, = \,\,62.8\,\,m{\text{ }}\)