\(\therefore \quad \omega_{1}=600 \pi\) or \(2 \pi v_{1}=600 \pi\) or \(v_{1}=300\)
\(A_{1}=4\)
and \(\omega_{2}=608 \pi\) or \(2 \pi \mathrm{v}_{2}=608 \pi\) or \(\mathrm{v}_{2}=304\)
\(A_{2}=5\)
Number of beats heard per second
\(=v_{2}-v_{1}=304-300=4 \)
\(\frac{I_{\max }}{I_{\min }}=\frac{\left(A_{1}+A_{2}\right)^{2}}{\left(A_{1}-A_{2}\right)^{2}}=\frac{(4+5)^{2}}{(4-5)^{2}}=\frac{81}{1}\)
(હવામાં ધ્વનિનો વેગ $330\;m/sec$ છે)