MCQ
Energy of photon whose frequency is ${10^{12}}MHz,$ will be
  • A
    $4.14 \times {10^3}keV$
  • B
    $4.14 \times {10^2}eV$
  • C
    $4.14 \times {10^3}MeV$
  • $4.14 \times {10^3}eV$

Answer

Correct option: D.
$4.14 \times {10^3}eV$
d
(d) $E(eV) = \frac{{h\nu }}{e} = \frac{{6.0 \times {{10}^{ - 34}} \times {{10}^{12}} \times {{10}^6}}}{{1.6 \times {{10}^{ - 19}}}}$$ = 4.14 \times {10^3}eV$.

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