MCQ
Equivalent weight of a bivalent metal is $37.2$. The molecular weight of its chloride is
- A$412.2$
- B$216$
- ✓$145.4$
- D$108.2$
$\therefore $ Atomic weight of metal $ = 37.2 \times 2 = 74.4$
$\therefore $ Formula of chloride $ = MC{l_2}$
Hence, molecular weight of chloride
$(MC{l_2}) = 74.4 + 2 \times 35.5 = 145.4$
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(I) Toluene
(II) $m - $dichlorobenzene
(III) $o - $dichlorobenzene
(IV)$p - $dichlorobenzene