Every atom makes one free electron in copper. If 1.1 ampere current is flowing in the wire of copper having 1, mm diameter, then the

Q: Every atom makes one free electron in copper. If $1.1$ $ampere$ current is flowing in the wire of copper having $1\, mm$ diameter, then the drift velocity (approx.) will be (Density of copper $ = 9 \times {10^3}\,kg\,{m^{ - 3}}$ and atomic weight = $63$)

b (b) Density of $Cu = 9 \times {10^3}\,kg/{m^3}$ (mass of $1$ $m^3$ of $Cu$) ( $6.0 \times 10^{23}$ atoms has a mass = $63 \times 10^{-3}\, kg$ Number of electrons per $m^3$ are $ = \frac{{6.0 \times {{10}^{23}}}}{{63 \times {{10}^{ - 3}}}} \times 9 \times {10^3} = 8.5 \times {10^{28}}$ Now drift velocity $ = {v_d} = \frac{i}{{neA}}$ $ = \frac{{1.1}}{{8.5 \times {{10}^{28}} \times 1.6 \times {{10}^{ - 19}} \times \pi \times {{(0.5 \times {{10}^{ - 3}})}^2}}}$ $ = 0.1 \times {10^{ - 3}}\,m\,/sec$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

Every atom makes one free electron in copper. If $1.1$ $ampere$ current is flowing in the wire of copper having $1\, mm$ diameter, then the drift velocity (approx.) will be (Density of copper $ = 9 \times {10^3}\,kg\,{m^{ - 3}}$ and atomic weight = $63$)

A$0.3\,mm/\sec $
B$0.1\,mm/\sec $
C$0.2\,mm/\sec $
D$0.2\,cm/\sec $

Diffcult

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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