Question
Express the $i^{-35}$ in the form $a+i b$

Answer

$i^{-35}$ $= \frac 1{i^{35}}$ $\frac 1{(i^2)^{17} i}$
$= \frac 1{-i} \times \frac i{i}$ $\frac i{-i^2} $ = i

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