Question
Factorise:
$6 x^2-17 x-3$

Answer

$6 x^2-17 x-3$
$=6 x^2-18 x+x-3$
$\{6 \times(-3)=-18,-18=-18 \times 1,-17=-18+1\}$
$=6 x(x-3)+1(x-3)$
$=(x-3)(6 x+1)$

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