So, $\left(3 \times 2 e ^{-}=6 e ^{-}\right) ; 2$ $NO$ can easily replaced $3 CO$.
$\left(6 \times 2 e ^{-}=12 e ^{-}\right) ; 4 NO$ can easily replace $6 CO$
$Fe ( CO )_{5} \rightarrow Fe ( NO )_{2}( CO )_{2}$
$Cr ( CO )_{5} \rightarrow Cr ( NO )_{4}$
સૂચિ $I$ સંકીર્ણ | સૂચિ $II$ $CFSE(\Delta_0)$ |
$A$ $\left[ Cu \left( NH _3\right)_6\right]^{2+}$ | $I$ $-0.6$ |
$B$ $\left[\operatorname{Ti}\left( N _2 O \right)_6\right]^{3+}$ | $II$ $-2.0$ |
$C$ $\left[ Fe ( CN )_6\right]^{3-}$ | $III$ $-1.2$ |
$D$ $\left[ NiF _6\right]^{4-}$ | $IV$ $-0.4$ |
નીચે આપેલા વિકલ્પોમાંથી સાચો જવાબ પસંદ કરો.
(પ.ક્ર.: $Mn\, = 25, Co\, = 27, Ni\, = 28, Zn\, = 30$)