$E_{cell}^o = E_{{\rm{cathode}}}^o - E_{{\rm{anode}}}^o$ $= -0.44 -(-0.14)= -0.30\,V$
The negative $EMF$ suggests that the reaction goes spontaneously in reversed direction.
$H_3PO_4 + OH^- \rightarrow H_2PO_4^- + H_2O$ ;
$H_3PO_4 + 2OH^- \rightarrow HPO_4^{2-} + 2H_2O$ ;
$H_3PO_4 + 3OH^- \rightarrow PO_4^{3-} + 3H_2O$