Figure shows a light bulb (B) and iron cored inductor connected to a dc battery through a switch (S).
- What will one observe when switch (S) is closed?
- How will the glow of the bulb change when the battery is replaced by an ac source of rms voltage equal to the voltage of dc battery? Justify your answer in each case.
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- When switch S is closed, the bulb will give full brightness slowly, because inductor opposes the rise of current in the circuit depending on the value of ratio $\frac{\text{L}}{\text{R}}.$
- When battery is replaced by an ac source, the inductor offers reactance $(\omega\text{L})$ so impedance of circuit increases and the bulb will glow with less brightness.
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